1. the compiler normally takes exponential numbers as doubles, so without the trailing f it will give you an error telling you that you must use a cast to convert double to float. 
   编译器通常会将指数作为双精度数(double)处理，所以假如没有这个尾随的f，就会收到一条出错提示，告诉我们须用一个“造型”将double转换成float。
2. if you multiply a float and a double, the result will be double; 
   若将一个float值与一个double值相乘，结果就是double；
3. deserves a closer look. Math.random( ) produces a double, so the value 26 is converted to a double to perform the multiplication, which also produces a double. 
   math.random()会产生一个double值，所以26会转换成double类型，以便执行乘法运算。这个运算也会产生一个double值。
4. The double result is turned back into a char with a cast. 
   利用一个“造型”，double结果会转换回char。
5. This means that ‘a’ must be converted to a double to perform the addition. 
   这意味着为了执行加法，必须无将'a'转换成一个double。

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